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  (#1)
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dynasty03's Avatar
 
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Join Date: March 23, 2003
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June 9, 2003, 07:39 PM

i got a question in class today....that i need help figuring it out....sorry if it's off topic but i want to know if anyone here could help me figure this out.
am not very good in figuring thinking problems out

1,000 = green street bikes (different models)

1,000 = red street bikes (different models)

#1. if 100 red bikes are taken from a garage and mixed into the second garage, then 100 bikes are taken from trhe second jar and put into the first garage

does the first garage have:

more _
_
less _ number of green bikes as the second garage has red?
_
same_



it might sound 1st grade math but i can't figure it out...if any one could help me...i would really appreciate it...sorry if to some if a boring topic.


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  (#2)
Knee Draggin!
 
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June 9, 2003, 07:45 PM

Ok, I realize that you put "bikes" in the equation, but this is definitely for the non-sportbike section........

- D


I know I wasn't doing 205 your honor, because my bike topped out at 145 last week......" *pauses* "I need NAWS."
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  (#3)
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June 9, 2003, 08:47 PM

I don't think there's enough information to determine the percentage of marbles in either jar or in your professor's head. I hated probability in school and even more now.


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  (#4)
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June 9, 2003, 09:07 PM

I say the SAME... considering "100 red bikes are taken from a garage" says "A" garage not one listed above and then suntracting the same amount of red and putting them in the green...
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June 9, 2003, 09:13 PM

Quote:
I say the SAME... considering "100 red bikes are taken from a garage" says "A" garage not one listed above and then suntracting the same amount of red and putting them in the green...
I agree w/ him...this sounds like high school math, nothing like college-level calculus.

if all else fails...look in the back of the book


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  (#6)
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June 9, 2003, 09:17 PM

This sounds like there are three garages. 1) A garage, 2)first garage, 3) third garage. Is this the way the problem is worded.Because if this is the case then Garage A will have 100 less bikes, and the first garage will have 100 more bikes. Just a thought,
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  (#7)
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June 9, 2003, 09:31 PM

I think its a straight probablility question (not some trick question) and I would guess it was originally worded with marbles in a jar. Assuming that there are only two jars/garages: when you take the 100 out of garage A (after mixing in the 100 red)..you will have the same number of green bikes/marbles in garage A as there are red bikes/marbles in garage/jar B.

Garage 1 - 1000 green
Garage 2 - 1000 red
-------------------------
Garage 1 - 1000 green 100 red, 1100 total (100 out of 1100 is 9 %)
Garage 2 - 900 red
-------------------------
Assuming the distribution is even when you pick your 100 bikes from garage 1, and there are 9 red bikes and 91 green bikes per 100 (9%) you would end up with
-------------------------
Garage 1 - 909 green 91 red, 1000 total
Garage 2 - 909 red 91 green, 1000 total

same # of green in #1 as red in #2

- D

[Edited on 6/10/2003 by onenamlynn]


I know I wasn't doing 205 your honor, because my bike topped out at 145 last week......" *pauses* "I need NAWS."
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  (#8)
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June 9, 2003, 09:40 PM

The same, No matter how you mix them up the # of green in one “jar” will always = the # of red in the other jar.

Take all 2000 and mix them together them seperate them into two "jars" of 1000 each,,
The # of green in on will = the # of red in the other.

Take 10 green objects and 10 red objects make 2 piles and try to make the green in one pile not = the red in the other..

[Edited on 10/6/2003 by y929va]
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  (#9)
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June 9, 2003, 09:55 PM

Quote:
The same, No matter how you mix them up the # of green in one “jar” will always = the # of red in the other jar.
yup, right on the money,.....

1000: red
1000: green
2000: total

2 jars,....

divide 2000 'units' (red & green) in half, into the 2 jars,.....

2 jars @ 1000 each, only either red or green!

x number red in one jar, MUST = x number of GREEN in OTHER jar,......


1000: red + 1000: green = 2000: total/2 jars,....

~ werd





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or that we are to stand by the president right or wrong, is not
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  (#10)
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June 9, 2003, 10:52 PM

Quote:
Assuming the distribution is even when you pick your 100 bikes from garage 1, and there are 9 red bikes and 91 green bikes per 100 (9%) you would end up with
Assumptions is the mother of all f#ckups. Just ask Lockheed about their Mars lander.

Kudos to y929va for seeing through the bullsh1t and using common sense.


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  (#11)
Knee Draggin!
 
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June 9, 2003, 11:26 PM

Priority inversion is a bitch..ain't it...

or was that the "oh my bad, you wanted that in meters?" incident

[Edited on 6/10/2003 by onenamlynn]


I know I wasn't doing 205 your honor, because my bike topped out at 145 last week......" *pauses* "I need NAWS."
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  (#12)
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June 10, 2003, 11:02 AM

it was originally marbles and jars...but i wanted to make it more interesting to post it here...

it wasn't a book question or anything is more of a thinking problems...i came up with the same conclusion as most of you here....thanks alot guys...


nicey
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